What are the solutions to the equation 4x(3x-7)=5 ?

The solutions to the equation 4x(3x-7)=5 are x= 5/2 ,x=-1/6

Find the zeros of 4x(3x-7)=5

The zeros of 4x(3x-7)=5 are x= 5/2 ,x=-1/6

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4 x (3 x - 7) = 5

x = \frac{5}{2}, x = - \frac{1}{6}

Solution steps

4 x (3 x - 7) = 5

Expand

4 x (3 x - 7) : 12 x^{2} - 28 x

12 x^{2} - 28 x = 5

Move

5

to the left side

12 x^{2} - 28 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

(- 28)^{2} - 4 \cdot 12 (- 5) = 32

x_{1, 2} = \frac{- ( - 28 ) \pm 32}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 32}{2 \cdot 12}, x_{2} = \frac{- ( - 28 ) - 32}{2 \cdot 12}

x = \frac{- ( - 28 ) + 32}{2 \cdot 12} : \frac{5}{2}

x = \frac{- ( - 28 ) - 32}{2 \cdot 12} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{6}

\frac{w ^{2}}{8} - \frac{w}{2} - 4 = 0

196 - x^{2}

(2 x - 3)^{2} - (x + 5)^{2} = - 23

x + 1 = 1

∣ 12 - 4 x ∣ < - 13

What are the solutions to the equation 4x(3x-7)=5 ?
The solutions to the equation 4x(3x-7)=5 are x= 5/2 ,x=-1/6
Find the zeros of 4x(3x-7)=5
The zeros of 4x(3x-7)=5 are x= 5/2 ,x=-1/6