What are the solutions to the equation 4k^2-4k+20=0 ?

The solutions to the equation 4k^2-4k+20=0 are k= 1/2+i(sqrt(19))/2 ,k= 1/2-i(sqrt(19))/2

Find the zeros of 4k^2-4k+20=0

The zeros of 4k^2-4k+20=0 are k= 1/2+i(sqrt(19))/2 ,k= 1/2-i(sqrt(19))/2

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4 k^{2} - 4 k + 20 = 0

k = \frac{1}{2} + i \frac{19}{2}, k = \frac{1}{2} - i \frac{19}{2}

Solution steps

4 k^{2} - 4 k + 20 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 20}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 20 : 419 i

k_{1, 2} = \frac{- ( - 4 ) \pm 4 19 i}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 4 19 i}{2 \cdot 4}, k_{2} = \frac{- ( - 4 ) - 4 19 i}{2 \cdot 4}

k = \frac{- ( - 4 ) + 4 19 i}{2 \cdot 4} : \frac{1}{2} + i \frac{19}{2}

k = \frac{- ( - 4 ) - 4 19 i}{2 \cdot 4} : \frac{1}{2} - i \frac{19}{2}

The solutions to the quadratic equation are:

k = \frac{1}{2} + i \frac{19}{2}, k = \frac{1}{2} - i \frac{19}{2}

3 n^{2} + 10 n = 5

- 2 x^{2} - 2 x + 12 = 0

2 x - 3 \geq - 4 x + 2

r^{2} - 16 r + 47 = - 5

x - 2 < 15

What are the solutions to the equation 4k^2-4k+20=0 ?
The solutions to the equation 4k^2-4k+20=0 are k= 1/2+i(sqrt(19))/2 ,k= 1/2-i(sqrt(19))/2
Find the zeros of 4k^2-4k+20=0
The zeros of 4k^2-4k+20=0 are k= 1/2+i(sqrt(19))/2 ,k= 1/2-i(sqrt(19))/2