What is the answer to (x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60 ?

The answer to (x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60 is x=7

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(x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60

(x - 2)^{3} - (x - 2) (x^{2} + 2 x + 4) + 6 (x - 2) (x + 2) = 60

x = 7

Solution steps

(x - 2)^{3} - (x - 2) (x^{2} + 2 x + 4) + 6 (x - 2) (x + 2) = 60

Expand

(x - 2)^{3} - (x - 2) (x^{2} + 2 x + 4) + 6 (x - 2) (x + 2) : 12 x - 24

12 x - 24 = 60

Move

24

to the right side

12 x = 84

Divide both sides by

12

x = 7

x, x + 4 y + 8 = 0

x, 6 x - 4 + 3 y = 2 x - 4 y + 6

x, f (x - 2) = 2 x - 1

4 t = 5 + 3

m, x - \frac{1}{x ^{2}} + 3 x + 2 = \frac{m}{x} + 2 + \frac{n}{x} + 1

What is the answer to (x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60 ?
The answer to (x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60 is x=7
Solve for x: (x-2)^3-(x-2)(x^2+2x+4)+6(x-2)(x+2)=60
The solution is x=7