What is the answer to solvefor a,2x^3+3x-1=10a ?

The answer to solvefor a,2x^3+3x-1=10a is a=(2x^3+3x-1)/(10)

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solvefor a,2x^3+3x-1=10a

solve for

a, 2 x^{3} + 3 x - 1 = 10 a

a = \frac{2 x ^{3} + 3 x - 1}{10}

Solution steps

2 x^{3} + 3 x - 1 = 10 a

Switch sides

10 a = 2 x^{3} + 3 x - 1

Divide both sides by

10

a = \frac{2 x ^{3} + 3 x - 1}{10}

a, p (x + 1) = a \cdot p (x)^{b}

x, (y - 6) 2 = 6 (x - 1)

e^{4} t + 2 = 4 e^{2} - t

x, - 12 x - 4 y + 20 = 0

y, x = y - p^{2}

What is the answer to solvefor a,2x^3+3x-1=10a ?
The answer to solvefor a,2x^3+3x-1=10a is a=(2x^3+3x-1)/(10)