What is the answer to (2x-5)(2x+5)-(2x+1)^2=4 ?

The answer to (2x-5)(2x+5)-(2x+1)^2=4 is x=-15/2

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(2x-5)(2x+5)-(2x+1)^2=4

(2 x - 5) (2 x + 5) - (2 x + 1)^{2} = 4

x = - \frac{15}{2}

Decimal Notation

x = - 7.5

Solution steps

(2 x - 5) (2 x + 5) - (2 x + 1)^{2} = 4

Expand

(2 x - 5) (2 x + 5) - (2 x + 1)^{2} : - 4 x - 26

- 4 x - 26 = 4

Move

26

to the right side

- 4 x = 30

Divide both sides by

- 4

x = - \frac{15}{2}

x, 3 x - 4 y = - 23

3 (x + 21) = 81

a, f = \frac{a}{b} - 3 c

\frac{x}{2} - 4 = 8, x

x - 2 + x - 2 = 0

What is the answer to (2x-5)(2x+5)-(2x+1)^2=4 ?
The answer to (2x-5)(2x+5)-(2x+1)^2=4 is x=-15/2
Solve for x: (2x-5)(2x+5)-(2x+1)^2=4
The solution is x=-15/2