What is the answer to solvefor t,s=v_{0}*t+1/2*a*l^2 ?

The answer to solvefor t,s=v_{0}*t+1/2*a*l^2 is t=(2s-l^2a)/(2v_{0)};\quad v_{0}\ne 0

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solvefor t,s=v_{0}t+1/2a*l^2

solve for

t, s = v_{0} \cdot t + \frac{1}{2} \cdot a \cdot l^{2}

t = \frac{2 s - l ^{2} a}{2 v _{0}}; v_{0} \neq = 0

Solution steps

s = v_{0} t + \frac{1}{2} a l^{2}

Switch sides

v_{0} t + \frac{1}{2} a l^{2} = s

Move

\frac{1}{2} \cdot a \cdot l^{2}

to the right side

v_{0} t = s - \frac{1}{2} a l^{2}

Divide both sides by

v_{0}; v_{0} \neq = 0

t = \frac{2 s - l ^{2} a}{2 v _{0}}; v_{0} \neq = 0

126 = (2 x)

y, - 11 - 3 y = 8 v + 1

x, p (x) = 2 y^{2} - 2 y

x, \frac{( 2 x + 3 )}{( 4 y + 1 )} = 3 + 2 x - 12 y

u, 2 u + 7 v = 52

What is the answer to solvefor t,s=v_{0}*t+1/2*a*l^2 ?
The answer to solvefor t,s=v_{0}*t+1/2*a*l^2 is t=(2s-l^2a)/(2v_{0)};\quad v_{0}\ne 0