What is the answer to solvefor p,p1^2-15r^1+50=0 ?

The answer to solvefor p,p1^2-15r^1+50=0 is p=15r-50

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solvefor p,p1^2-15r^1+50=0

solve for

p, p 1^{2} - 15 r^{1} + 50 = 0

p = 15 r - 50

Solution steps

p \cdot 1^{2} - 15 r^{1} + 50 = 0

Apply rule

1^{a} = 1

1^{2} = 1

1 \cdot p - 15 r^{1} + 50 = 0

Apply rule

a^{1} = a

r^{1} = r

1 \cdot p - 15 r + 50 = 0

Multiply:

p \cdot 1 = p

p - 15 r + 50 = 0

Move

15 r

to the right side

p + 50 = 15 r

Move

50

to the right side

p = 15 r - 50

\frac{91}{4} = \frac{y - 11}{3}

t (n) = 4 t (\frac{n}{2}) + n^{3}

x, 5 x - 3 + 2 y = 3 x + 3 - 2 y + x

2 - 11 x = 4 x + 17

2500000 - 2425000 = 0.75 x - x

What is the answer to solvefor p,p1^2-15r^1+50=0 ?
The answer to solvefor p,p1^2-15r^1+50=0 is p=15r-50