What is factor n^4+6n^3+13n^2+12n+4 ?

The solution to factor n^4+6n^3+13n^2+12n+4 is (n+1)^2(n+2)^2

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factor n^4+6n^3+13n^2+12n+4

factor

n^{4} + 6 n^{3} + 13 n^{2} + 12 n + 4

(n + 1)^{2} (n + 2)^{2}

Solution steps

n^{4} + 6 n^{3} + 13 n^{2} + 12 n + 4

Use the rational root theorem

= (n + 1) \frac{n ^{4} + 6 n ^{3} + 13 n ^{2} + 12 n + 4}{n + 1}

\frac{n ^{4} + 6 n ^{3} + 13 n ^{2} + 12 n + 4}{n + 1} = n^{3} + 5 n^{2} + 8 n + 4

= (n + 1) (n^{3} + 5 n^{2} + 8 n + 4)

Factor

n^{3} + 5 n^{2} + 8 n + 4 : (n + 1) (n + 2) (n + 2)

= (n + 1) (n + 1) (n + 2) (n + 2)

Simplify

= (n + 1)^{2} (n + 2)^{2}

a^{2} - 2 a

x - \frac{2 x - 1}{3} = \frac{3 x - 5}{5}

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) + 4 = 0

\frac{13}{2} - 5

\frac{a - b}{b - a}

What is factor n^4+6n^3+13n^2+12n+4 ?
The solution to factor n^4+6n^3+13n^2+12n+4 is (n+1)^2(n+2)^2