What are the solutions to the equation z^3=-1 ?

The solutions to the equation z^3=-1 are z=-1,z= 1/2-(sqrt(3))/2 i,z= 1/2+(sqrt(3))/2 i

Find the zeros of z^3=-1

The zeros of z^3=-1 are z=-1,z= 1/2-(sqrt(3))/2 i,z= 1/2+(sqrt(3))/2 i

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z^{3} = - 1

z = - 1, z = \frac{1}{2} - \frac{3}{2} i, z = \frac{1}{2} + \frac{3}{2} i

Solution steps

z^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

z = - 1, z = \frac{1}{2} - \frac{3}{2} i, z = \frac{1}{2} + \frac{3}{2} i

(x + 2) (x + 4) (x + 6) (x + 12) + 4 x^{2} = 0

x^{6} - 1 = 0

- x^{3} + 7 x - 6 = 0

(4 x - 5)^{4} = 81

m^{3} + 1 = 0

What are the solutions to the equation z^3=-1 ?
The solutions to the equation z^3=-1 are z=-1,z= 1/2-(sqrt(3))/2 i,z= 1/2+(sqrt(3))/2 i
Find the zeros of z^3=-1
The zeros of z^3=-1 are z=-1,z= 1/2-(sqrt(3))/2 i,z= 1/2+(sqrt(3))/2 i