What are the solutions to the equation x^3-4x^2-x+10=0 ?

The solutions to the equation x^3-4x^2-x+10=0 are x=2,x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x^3-4x^2-x+10=0

The zeros of x^3-4x^2-x+10=0 are x=2,x=1+sqrt(6),x=1-sqrt(6)

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x^{3} - 4 x^{2} - x + 10 = 0

x = 2, x = 1 + 6, x = 1 - 6

Decimal Notation

x = 2, x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x^{3} - 4 x^{2} - x + 10 = 0

Factor

x^{3} - 4 x^{2} - x + 10 : (x - 2) (x^{2} - 2 x - 5)

(x - 2) (x^{2} - 2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 2 x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 2 x - 5 = 0 : x = 1 + 6, x = 1 - 6

The solutions are

x = 2, x = 1 + 6, x = 1 - 6

x^{3} - x^{2} - x - 2 = 0

e a^{4} = 5, a^{1} = 20

1 x^{3} - 1 x^{2} - 2 x + 2 = 0

x^{5} = 1

x^{3} - 27 = 0

What are the solutions to the equation x^3-4x^2-x+10=0 ?
The solutions to the equation x^3-4x^2-x+10=0 are x=2,x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x^3-4x^2-x+10=0
The zeros of x^3-4x^2-x+10=0 are x=2,x=1+sqrt(6),x=1-sqrt(6)