What are the solutions to the equation 1x^3-1x^2-2x+2=0 ?

The solutions to the equation 1x^3-1x^2-2x+2=0 are x=1,x=-sqrt(2),x=sqrt(2)

Find the zeros of 1x^3-1x^2-2x+2=0

The zeros of 1x^3-1x^2-2x+2=0 are x=1,x=-sqrt(2),x=sqrt(2)

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1 x^{3} - 1 x^{2} - 2 x + 2 = 0

x = 1, x = - 2, x = 2

Decimal Notation

x = 1, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

1 \cdot x^{3} - 1 \cdot x^{2} - 2 x + 2 = 0

Refine

x^{3} - x^{2} - 2 x + 2 = 0

Factor

x^{3} - x^{2} - 2 x + 2 : (x - 1) (x + 2) (x - 2)

(x - 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = - 2, x = 2

x^{5} = 1

x^{3} - 27 = 0

9 x^{4} - 10 x^{2} + 1 = 0

4 b^{3} - 6 b^{2} + 1 = 0

x^{3} + x - 16 = 0

What are the solutions to the equation 1x^3-1x^2-2x+2=0 ?
The solutions to the equation 1x^3-1x^2-2x+2=0 are x=1,x=-sqrt(2),x=sqrt(2)
Find the zeros of 1x^3-1x^2-2x+2=0
The zeros of 1x^3-1x^2-2x+2=0 are x=1,x=-sqrt(2),x=sqrt(2)