What are the solutions to the equation 9x^4-10x^2+1=0 ?

The solutions to the equation 9x^4-10x^2+1=0 are x=1,x=-1,x= 1/3 ,x=-1/3

Find the zeros of 9x^4-10x^2+1=0

The zeros of 9x^4-10x^2+1=0 are x=1,x=-1,x= 1/3 ,x=-1/3

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9 x^{4} - 10 x^{2} + 1 = 0

x = 1, x = - 1, x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 1, x = 0.33333 \dots, x = - 0.33333 \dots

Solution steps

9 x^{4} - 10 x^{2} + 1 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

9 u^{2} - 10 u + 1 = 0

Solve

9 u^{2} - 10 u + 1 = 0 : u = 1, u = \frac{1}{9}

u = 1, u = \frac{1}{9}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = \frac{1}{9} : x = \frac{1}{3}, x = - \frac{1}{3}

The solutions are

x = 1, x = - 1, x = \frac{1}{3}, x = - \frac{1}{3}

4 b^{3} - 6 b^{2} + 1 = 0

x^{3} + x - 16 = 0

x^{4} - (5 + 2) \cdot x^{2} + 10 = 0

(x^{2} + x - 6) (x^{2} - 3 x - 4) = 24

x, (3 x + 7)^{5} = 2 y^{3}

What are the solutions to the equation 9x^4-10x^2+1=0 ?
The solutions to the equation 9x^4-10x^2+1=0 are x=1,x=-1,x= 1/3 ,x=-1/3
Find the zeros of 9x^4-10x^2+1=0
The zeros of 9x^4-10x^2+1=0 are x=1,x=-1,x= 1/3 ,x=-1/3