What are the solutions to the equation 4m^3+4m^2-7m+2=0 ?

The solutions to the equation 4m^3+4m^2-7m+2=0 are m=-2,m= 1/2

Find the zeros of 4m^3+4m^2-7m+2=0

The zeros of 4m^3+4m^2-7m+2=0 are m=-2,m= 1/2

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4 m^{3} + 4 m^{2} - 7 m + 2 = 0

m = - 2, m = \frac{1}{2}

Decimal Notation

m = - 2, m = 0.5

Solution steps

4 m^{3} + 4 m^{2} - 7 m + 2 = 0

Factor

4 m^{3} + 4 m^{2} - 7 m + 2 : (m + 2) (2 m - 1)^{2}

(m + 2) (2 m - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 2 = 0 or 2 m - 1 = 0

Solve

m + 2 = 0 : m = - 2

Solve

2 m - 1 = 0 : m = \frac{1}{2}

The solutions are

m = - 2, m = \frac{1}{2}

x, x^{3} + y^{3} = 0

2 m \cdot m^{2} = m^{2}

8 (x^{3} - x^{2} + x) + 2 x (4 x^{2} - 4 x + 1) = 30

x^{4} - 13 x^{2} + 5 x = 0

x^{3} + 216 = 0

What are the solutions to the equation 4m^3+4m^2-7m+2=0 ?
The solutions to the equation 4m^3+4m^2-7m+2=0 are m=-2,m= 1/2
Find the zeros of 4m^3+4m^2-7m+2=0
The zeros of 4m^3+4m^2-7m+2=0 are m=-2,m= 1/2