What are the solutions to the equation x^3-8x^2+12x+9=0 ?

The solutions to the equation x^3-8x^2+12x+9=0 are x=3,x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2

Find the zeros of x^3-8x^2+12x+9=0

The zeros of x^3-8x^2+12x+9=0 are x=3,x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2

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x^{3} - 8 x^{2} + 12 x + 9 = 0

x = 3, x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

Decimal Notation

x = 3, x = 5.54138 \dots, x = - 0.54138 \dots

Solution steps

x^{3} - 8 x^{2} + 12 x + 9 = 0

Factor

x^{3} - 8 x^{2} + 12 x + 9 : (x - 3) (x^{2} - 5 x - 3)

(x - 3) (x^{2} - 5 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} - 5 x - 3 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} - 5 x - 3 = 0 : x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

The solutions are

x = 3, x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

z^{5} = 1

x^{4} + 3 x^{2} + 2 = 0

x, f \cdot g = (x^{2} + 1)^{10}

d^{3} - d^{2} - 4 d + 4 = 0

(x^{2} + x) (x^{2} + x - 8) + 12 = 0

What are the solutions to the equation x^3-8x^2+12x+9=0 ?
The solutions to the equation x^3-8x^2+12x+9=0 are x=3,x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2
Find the zeros of x^3-8x^2+12x+9=0
The zeros of x^3-8x^2+12x+9=0 are x=3,x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2