What are the solutions to the equation d^3-d^2-4d+4=0 ?

The solutions to the equation d^3-d^2-4d+4=0 are d=1,d=-2,d=2

Find the zeros of d^3-d^2-4d+4=0

The zeros of d^3-d^2-4d+4=0 are d=1,d=-2,d=2

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d^{3} - d^{2} - 4 d + 4 = 0

d = 1, d = - 2, d = 2

Solution steps

d^{3} - d^{2} - 4 d + 4 = 0

Factor

d^{3} - d^{2} - 4 d + 4 : (d - 1) (d + 2) (d - 2)

(d - 1) (d + 2) (d - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

d - 1 = 0 or d + 2 = 0 or d - 2 = 0

Solve

d - 1 = 0 : d = 1

Solve

d + 2 = 0 : d = - 2

Solve

d - 2 = 0 : d = 2

The solutions are

d = 1, d = - 2, d = 2

(x^{2} + x) (x^{2} + x - 8) + 12 = 0

r^{3} - 7 r + 6 = 0

x^{3} + x^{2} = 16 x - 20

x^{3} + 2 x^{2} - x - 2 = 0

x^{3} - 16 = 0

What are the solutions to the equation d^3-d^2-4d+4=0 ?
The solutions to the equation d^3-d^2-4d+4=0 are d=1,d=-2,d=2
Find the zeros of d^3-d^2-4d+4=0
The zeros of d^3-d^2-4d+4=0 are d=1,d=-2,d=2