What are the solutions to the equation -9x^2-12x-4=0 ?

The solutions to the equation -9x^2-12x-4=0 are x=-2/3

Find the zeros of -9x^2-12x-4=0

The zeros of -9x^2-12x-4=0 are x=-2/3

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- 9 x^{2} - 12 x - 4 = 0

x = - \frac{2}{3}

Solution steps

- 9 x^{2} - 12 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 9 ) ( - 4 )}{2 ( - 9 )}

(- 12)^{2} - 4 (- 9) (- 4) = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 ( - 9 )}

x = \frac{- ( - 12 )}{2 ( - 9 )}

\frac{- ( - 12 )}{2 ( - 9 )} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

17 w - 1 > - 18

2 w^{2} - 3 w - 65 = 0

∣ x - 2 ∣ + 2 < 3

\frac{x ^{2 n + 1}}{x ^{2 n - 1}}

6 x - 30

What are the solutions to the equation -9x^2-12x-4=0 ?
The solutions to the equation -9x^2-12x-4=0 are x=-2/3
Find the zeros of -9x^2-12x-4=0
The zeros of -9x^2-12x-4=0 are x=-2/3