What are the solutions to the equation 4x+3=x^3+3x^2-9x-12 ?

The solutions to the equation 4x+3=x^3+3x^2-9x-12 are x=-1,x=3,x=-5

Find the zeros of 4x+3=x^3+3x^2-9x-12

The zeros of 4x+3=x^3+3x^2-9x-12 are x=-1,x=3,x=-5

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4 x + 3 = x^{3} + 3 x^{2} - 9 x - 12

x = - 1, x = 3, x = - 5

Solution steps

4 x + 3 = x^{3} + 3 x^{2} - 9 x - 12

Switch sides

x^{3} + 3 x^{2} - 9 x - 12 = 4 x + 3

Move

3

to the left side

x^{3} + 3 x^{2} - 9 x - 15 = 4 x

Move

4 x

to the left side

x^{3} + 3 x^{2} - 13 x - 15 = 0

Factor

x^{3} + 3 x^{2} - 13 x - 15 : (x + 1) (x - 3) (x + 5)

(x + 1) (x - 3) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0 or x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 1, x = 3, x = - 5

x^{3} - x^{2} - 5 x - 3 = 0

5 x^{3} + 23 x^{2} + 20 x - 12 = 0

x^{3} - x - 3360 = 0

b^{3} + 2 b^{2} - 10 b - 19 = 0

x, x^{3} + y^{3} = x^{3} y^{3}

What are the solutions to the equation 4x+3=x^3+3x^2-9x-12 ?
The solutions to the equation 4x+3=x^3+3x^2-9x-12 are x=-1,x=3,x=-5
Find the zeros of 4x+3=x^3+3x^2-9x-12
The zeros of 4x+3=x^3+3x^2-9x-12 are x=-1,x=3,x=-5