What are the solutions to the equation -((x^4))/(10)+14/15*x^3-2x^2=0 ?

The solutions to the equation -((x^4))/(10)+14/15*x^3-2x^2=0 are x=0,x=6,x= 10/3

Find the zeros of -((x^4))/(10)+14/15*x^3-2x^2=0

The zeros of -((x^4))/(10)+14/15*x^3-2x^2=0 are x=0,x=6,x= 10/3

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- \frac{( x ^{4} )}{10} + \frac{14}{15} \cdot x^{3} - 2 x^{2} = 0

x = 0, x = 6, x = \frac{10}{3}

Decimal Notation

x = 0, x = 6, x = 3.33333 \dots

Solution steps

- \frac{( x ^{4} )}{10} + \frac{14}{15} x^{3} - 2 x^{2} = 0

Factor

- \frac{x ^{4}}{10} + \frac{14}{15} x^{3} - 2 x^{2} : - x^{2} (\frac{x ^{2}}{10} - \frac{14 x}{15} + 2)

- x^{2} (\frac{x ^{2}}{10} - \frac{14 x}{15} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or \frac{x ^{2}}{10} - \frac{14 x}{15} + 2 = 0

Solve

\frac{x ^{2}}{10} - \frac{14 x}{15} + 2 = 0 : x = 6, x = \frac{10}{3}

The solutions are

x = 0, x = 6, x = \frac{10}{3}

x^{2} (x^{2} - 9) = - 20

(x - 1)^{3} = x - 1

2 (x - 2)^{3} + 8 = 136

x^{3} - 11 x^{2} + 32 x - 28 = 0

3 x^{3} - 4 x^{2} + 4 x = 16

What are the solutions to the equation -((x^4))/(10)+14/15*x^3-2x^2=0 ?
The solutions to the equation -((x^4))/(10)+14/15*x^3-2x^2=0 are x=0,x=6,x= 10/3
Find the zeros of -((x^4))/(10)+14/15*x^3-2x^2=0
The zeros of -((x^4))/(10)+14/15*x^3-2x^2=0 are x=0,x=6,x= 10/3