What are the solutions to the equation (2x+3)^3=-16 ?

The solutions to the equation (2x+3)^3=-16 are x=(-2\sqrt[3]{2}-3)/2

Find the zeros of (2x+3)^3=-16

The zeros of (2x+3)^3=-16 are x=(-2\sqrt[3]{2}-3)/2

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(2 x + 3)^{3} = - 16

Decimal Notation

x = - 2.75992 \dots

Solution steps

(2 x + 3)^{3} = - 16

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

lo g_{10} (10) (x^{3} + 5) = 3 lo g_{10} (10) (x + 2)

d^{3} + d^{2} + 4 d + 4 = 0

x^{5} - x - 1 = 0

x^{3} - 2 x^{3} + 1 = 28

(x + 4)^{2} (x - 3)^{2} = (x + 5)^{2}

What are the solutions to the equation (2x+3)^3=-16 ?
The solutions to the equation (2x+3)^3=-16 are x=(-2\sqrt[3]{2}-3)/2
Find the zeros of (2x+3)^3=-16
The zeros of (2x+3)^3=-16 are x=(-2\sqrt[3]{2}-3)/2