What are the solutions to the equation 6c^2+20c-25-c^3=0 ?

The solutions to the equation 6c^2+20c-25-c^3=0 are c=1,c=(5+5sqrt(5))/2 ,c=(5-5sqrt(5))/2

Find the zeros of 6c^2+20c-25-c^3=0

The zeros of 6c^2+20c-25-c^3=0 are c=1,c=(5+5sqrt(5))/2 ,c=(5-5sqrt(5))/2

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6 c^{2} + 20 c - 25 - c^{3} = 0

c = 1, c = \frac{5 + 5 5}{2}, c = \frac{5 - 5 5}{2}

Decimal

c = 1, c = 8.09016 \dots, c = - 3.09016 \dots

Solution steps

6 c^{2} + 20 c - 25 - c^{3} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- c^{3} + 6 c^{2} + 20 c - 25 = 0

Factor

- c^{3} + 6 c^{2} + 20 c - 25 : - (c - 1) (c^{2} - 5 c - 25)

- (c - 1) (c^{2} - 5 c - 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c - 1 = 0 or c^{2} - 5 c - 25 = 0

Solve

c - 1 = 0 : c = 1

Solve

c^{2} - 5 c - 25 = 0 : c = \frac{5 + 5 5}{2}, c = \frac{5 - 5 5}{2}

The solutions are

c = 1, c = \frac{5 + 5 5}{2}, c = \frac{5 - 5 5}{2}

r^{4} = 4

43 - 2 (x + 3)^{4} = 11

(x + 11)^{4} = 169

2 x^{4} - 13 x^{3} + 28 x^{2} = 23 x - 6

x, lo g_{10} (y) = - x^{3}

What are the solutions to the equation 6c^2+20c-25-c^3=0 ?
The solutions to the equation 6c^2+20c-25-c^3=0 are c=1,c=(5+5sqrt(5))/2 ,c=(5-5sqrt(5))/2
Find the zeros of 6c^2+20c-25-c^3=0
The zeros of 6c^2+20c-25-c^3=0 are c=1,c=(5+5sqrt(5))/2 ,c=(5-5sqrt(5))/2