What are the solutions to the equation x^3-7(x^2)+6=0 ?

The solutions to the equation x^3-7(x^2)+6=0 are x=1,x=3+sqrt(15),x=3-sqrt(15)

Find the zeros of x^3-7(x^2)+6=0

The zeros of x^3-7(x^2)+6=0 are x=1,x=3+sqrt(15),x=3-sqrt(15)

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x^{3} - 7 (x^{2}) + 6 = 0

x = 1, x = 3 + 15, x = 3 - 15

Decimal Notation

x = 1, x = 6.87298 \dots, x = - 0.87298 \dots

Solution steps

x^{3} - 7 (x^{2}) + 6 = 0

Refine

x^{3} - 7 x^{2} + 6 = 0

Factor

x^{3} - 7 x^{2} + 6 : (x - 1) (x^{2} - 6 x - 6)

(x - 1) (x^{2} - 6 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 6 x - 6 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 6 x - 6 = 0 : x = 3 + 15, x = 3 - 15

The solutions are

x = 1, x = 3 + 15, x = 3 - 15

(2 x + 1)^{3} = - 8

n^{3} = (n)^{2}

32 m^{3} - 5 m^{2} + 26 m - 1 = 0

a^{4} - 14 a^{2} + 24 = 0

15 x^{3} + 27 x^{2} + 3 x - 3 = 0

What are the solutions to the equation x^3-7(x^2)+6=0 ?
The solutions to the equation x^3-7(x^2)+6=0 are x=1,x=3+sqrt(15),x=3-sqrt(15)
Find the zeros of x^3-7(x^2)+6=0
The zeros of x^3-7(x^2)+6=0 are x=1,x=3+sqrt(15),x=3-sqrt(15)