What are the solutions to the equation n^3=(n)^2 ?

The solutions to the equation n^3=(n)^2 are n=0,n=1

Find the zeros of n^3=(n)^2

The zeros of n^3=(n)^2 are n=0,n=1

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n^{3} = (n)^{2}

n = 0, n = 1

Solution steps

n^{3} = n^{2}

Move

n^{2}

to the left side

n^{3} - n^{2} = 0

Factor

n^{3} - n^{2} : n^{2} (n - 1)

n^{2} (n - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n = 0 or n - 1 = 0

Solve

n - 1 = 0 : n = 1

The solutions are

n = 0, n = 1

32 m^{3} - 5 m^{2} + 26 m - 1 = 0

a^{4} - 14 a^{2} + 24 = 0

15 x^{3} + 27 x^{2} + 3 x - 3 = 0

(\frac{x + 1}{2})^{3} = \frac{- 1}{8}

r^{3} + 10 r^{2} + 33 r - 29 = 0

What are the solutions to the equation n^3=(n)^2 ?
The solutions to the equation n^3=(n)^2 are n=0,n=1
Find the zeros of n^3=(n)^2
The zeros of n^3=(n)^2 are n=0,n=1