What are the solutions to the equation 28a^{12}=56a^{15} ?

The solutions to the equation 28a^{12}=56a^{15} are

Find the zeros of 28a^{12}=56a^{15}

The zeros of 28a^{12}=56a^{15} are

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28 a^{12} = 56 a^{15}

Solution steps

28 a^{12} = 56 a^{15}

Move

56 a^{15}

to the left side

28 a^{12} - 56 a^{15} = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

The solutions are

\frac{x ^{13}}{3 ^{7}} = 3^{6}

x^{3} + 9 x^{2} + 18 x = 2168

m^{3} - m^{2} + 2 = 0

(\frac{x + 2}{3})^{4} = 128

x^{4} - 4 x + 4 = 0

What are the solutions to the equation 28a^{12}=56a^{15} ?
The solutions to the equation 28a^{12}=56a^{15} are
Find the zeros of 28a^{12}=56a^{15}
The zeros of 28a^{12}=56a^{15} are