What are the solutions to the equation x=33x^2+4x^3-10x^2 ?

The solutions to the equation x=33x^2+4x^3-10x^2 are x=0,x=(-23+sqrt(545))/8 ,x=(-23-sqrt(545))/8

Find the zeros of x=33x^2+4x^3-10x^2

The zeros of x=33x^2+4x^3-10x^2 are x=0,x=(-23+sqrt(545))/8 ,x=(-23-sqrt(545))/8

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x = 33 x^{2} + 4 x^{3} - 10 x^{2}

x = 0, x = \frac{- 23 + 545}{8}, x = \frac{- 23 - 545}{8}

Decimal Notation

x = 0, x = 0.04315 \dots, x = - 5.79315 \dots

Solution steps

x = 33 x^{2} + 4 x^{3} - 10 x^{2}

Switch sides

33 x^{2} + 4 x^{3} - 10 x^{2} = x

Move

x

to the left side

4 x^{3} + 23 x^{2} - x = 0

Factor

4 x^{3} + 23 x^{2} - x : x (4 x^{2} + 23 x - 1)

x (4 x^{2} + 23 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x^{2} + 23 x - 1 = 0

Solve

4 x^{2} + 23 x - 1 = 0 : x = \frac{- 23 + 545}{8}, x = \frac{- 23 - 545}{8}

The solutions are

x = 0, x = \frac{- 23 + 545}{8}, x = \frac{- 23 - 545}{8}

0.001 x^{3} = - 8

6 = 20 + 12 t^{2} - t^{3}

x^{6} - 5 x^{3} - 16 = 0

(x - 5) \cdot x^{2} = 14

2 x^{3} = 0

What are the solutions to the equation x=33x^2+4x^3-10x^2 ?
The solutions to the equation x=33x^2+4x^3-10x^2 are x=0,x=(-23+sqrt(545))/8 ,x=(-23-sqrt(545))/8
Find the zeros of x=33x^2+4x^3-10x^2
The zeros of x=33x^2+4x^3-10x^2 are x=0,x=(-23+sqrt(545))/8 ,x=(-23-sqrt(545))/8