What are the solutions to the equation (x^2+1)(1-7x)=0 ?

The solutions to the equation (x^2+1)(1-7x)=0 are x=i,x=-i,x= 1/7

Find the zeros of (x^2+1)(1-7x)=0

The zeros of (x^2+1)(1-7x)=0 are x=i,x=-i,x= 1/7

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(x^{2} + 1) (1 - 7 x) = 0

x = i, x = - i, x = \frac{1}{7}

Solution steps

(x^{2} + 1) (1 - 7 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0 or 1 - 7 x = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

1 - 7 x = 0 : x = \frac{1}{7}

The solutions are

x = i, x = - i, x = \frac{1}{7}

x^{4} - 4 x^{3} - 4 x^{2} - 10 = 0

x^{4} - 8 x^{2} + x + 12 = 0

z^{3} + z^{2} + z + 1 = 0

(2 x - 1)^{4} - 16 = 0

(x - 5)^{3} = 0

What are the solutions to the equation (x^2+1)(1-7x)=0 ?
The solutions to the equation (x^2+1)(1-7x)=0 are x=i,x=-i,x= 1/7
Find the zeros of (x^2+1)(1-7x)=0
The zeros of (x^2+1)(1-7x)=0 are x=i,x=-i,x= 1/7