What are the solutions to the equation (2x-1)^4-16=0 ?

The solutions to the equation (2x-1)^4-16=0 are x= 3/2 ,x=-1/2

Find the zeros of (2x-1)^4-16=0

The zeros of (2x-1)^4-16=0 are x= 3/2 ,x=-1/2

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(2 x - 1)^{4} - 16 = 0

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

(2 x - 1)^{4} - 16 = 0

Move

16

to the right side

(2 x - 1)^{4} = 16

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = \frac{3}{2}, x = - \frac{1}{2}

(x - 5)^{3} = 0

12 x^{5} = (4 x^{2}) (c)

5 x^{27} x - 53 = 0

m^{4} + 2 m^{3} + 2 m^{2} = 0

x^{3} + x^{2} - x - 10 = 0

What are the solutions to the equation (2x-1)^4-16=0 ?
The solutions to the equation (2x-1)^4-16=0 are x= 3/2 ,x=-1/2
Find the zeros of (2x-1)^4-16=0
The zeros of (2x-1)^4-16=0 are x= 3/2 ,x=-1/2