What are the solutions to the equation 12x^5=(4x^2)(c) ?

The solutions to the equation 12x^5=(4x^2)(c) are

Find the zeros of 12x^5=(4x^2)(c)

The zeros of 12x^5=(4x^2)(c) are

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12 x^{5} = (4 x^{2}) (c)

Solution steps

12 x^{5} = (4 x^{2}) (c)

Move

(4 x^{2}) (c)

to the left side

12 x^{5} - 4 x^{2} c = 0

Factor

12 x^{5} - 4 x^{2} c : 4 x^{2} (3 x^{3} - c)

4 x^{2} (3 x^{3} - c) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{3} - c = 0

Solve

The solutions are

5 x^{27} x - 53 = 0

m^{4} + 2 m^{3} + 2 m^{2} = 0

x^{3} + x^{2} - x - 10 = 0

(x + 2) (2 x^{2} - 5 x) - x^{3} = 8

x, x^{3} + y^{3} + z^{3} = k^{1} - 100

What are the solutions to the equation 12x^5=(4x^2)(c) ?
The solutions to the equation 12x^5=(4x^2)(c) are
Find the zeros of 12x^5=(4x^2)(c)
The zeros of 12x^5=(4x^2)(c) are