What are the solutions to the equation (2n)3n(6)=3n^3(7) ?

The solutions to the equation (2n)3n(6)=3n^3(7) are n=0,n= 12/7

Find the zeros of (2n)3n(6)=3n^3(7)

The zeros of (2n)3n(6)=3n^3(7) are n=0,n= 12/7

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(2 n) 3 n (6) = 3 n^{3} (7)

n = 0, n = \frac{12}{7}

Decimal Notation

n = 0, n = 1.71428 \dots

Solution steps

(2 n) \cdot 3 n (6) = 3 n^{3} (7)

Move

3 n^{3} (7)

to the left side

2 n \cdot 3 n \cdot 6 - 3 n^{3} \cdot 7 = 0

Factor

2 n \cdot 3 n \cdot 6 - 3 n^{3} \cdot 7 : 3 n^{2} (12 - 7 n)

3 n^{2} (12 - 7 n) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n = 0 or 12 - 7 n = 0

Solve

12 - 7 n = 0 : n = \frac{12}{7}

The solutions are

n = 0, n = \frac{12}{7}

x^{3} - x - 10 = 0

x^{3} - 2 x^{2} - 5 x - 10 = 0

x, x^{5} + 5 r^{2} - 1 = 0

(3 x^{3} - 2 x^{2} - 7 x) = 2

x^{3} - x^{2} - 8 x + 12 = 0

What are the solutions to the equation (2n)3n(6)=3n^3(7) ?
The solutions to the equation (2n)3n(6)=3n^3(7) are n=0,n= 12/7
Find the zeros of (2n)3n(6)=3n^3(7)
The zeros of (2n)3n(6)=3n^3(7) are n=0,n= 12/7