What are the solutions to the equation 2x^3+6x^2-x-3=0 ?

The solutions to the equation 2x^3+6x^2-x-3=0 are x=-3,x=-1/(sqrt(2)),x= 1/(sqrt(2))

Find the zeros of 2x^3+6x^2-x-3=0

The zeros of 2x^3+6x^2-x-3=0 are x=-3,x=-1/(sqrt(2)),x= 1/(sqrt(2))

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2 x^{3} + 6 x^{2} - x - 3 = 0

x = - 3, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal

x = - 3, x = - 0.70710 \dots, x = 0.70710 \dots

Solution steps

2 x^{3} + 6 x^{2} - x - 3 = 0

Factor

2 x^{3} + 6 x^{2} - x - 3 : (x + 3) (2 x + 1) (2 x - 1)

(x + 3) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 3, x = - \frac{1}{2}, x = \frac{1}{2}

1 - (p + 3)^{3} = - 8

(4^{2} - x)^{4} = 16

2 = (\frac{1 + r}{100})^{6}

2 x^{4} - x^{3} - 3 x^{2} - 9 x - 4 = 0

(x) = 0.04 x^{3} - 2 x^{2} + 60 x + 200

What are the solutions to the equation 2x^3+6x^2-x-3=0 ?
The solutions to the equation 2x^3+6x^2-x-3=0 are x=-3,x=-1/(sqrt(2)),x= 1/(sqrt(2))
Find the zeros of 2x^3+6x^2-x-3=0
The zeros of 2x^3+6x^2-x-3=0 are x=-3,x=-1/(sqrt(2)),x= 1/(sqrt(2))