What are the solutions to the equation 5=(1+x)^{12} ?

The solutions to the equation 5=(1+x)^{12} are x=\sqrt[12]{5}-1,x=-\sqrt[12]{5}-1

Find the zeros of 5=(1+x)^{12}

The zeros of 5=(1+x)^{12} are x=\sqrt[12]{5}-1,x=-\sqrt[12]{5}-1

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5 = (1 + x)^{12}

Decimal Notation

x = 0.14352 \dots, x = - 2.14352 \dots

Solution steps

5 = (1 + x)^{12}

Switch sides

(1 + x)^{12} = 5

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

(2 x + 1)^{3} = 9.81

\frac{x ^{4}}{2 + 5} = 18.5

d^{3} - 4 d^{2} + 5 d - 2 = 0

d^{3} + 1 = 0

x, x^{3} - y^{3} = 0

What are the solutions to the equation 5=(1+x)^{12} ?
The solutions to the equation 5=(1+x)^{12} are x=\sqrt[12]{5}-1,x=-\sqrt[12]{5}-1
Find the zeros of 5=(1+x)^{12}
The zeros of 5=(1+x)^{12} are x=\sqrt[12]{5}-1,x=-\sqrt[12]{5}-1