What are the solutions to the equation d^3+1=0 ?

The solutions to the equation d^3+1=0 are d=-1,d= 1/2-(sqrt(3))/2 i,d= 1/2+(sqrt(3))/2 i

Find the zeros of d^3+1=0

The zeros of d^3+1=0 are d=-1,d= 1/2-(sqrt(3))/2 i,d= 1/2+(sqrt(3))/2 i

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d^{3} + 1 = 0

d = - 1, d = \frac{1}{2} - \frac{3}{2} i, d = \frac{1}{2} + \frac{3}{2} i

Solution steps

d^{3} + 1 = 0

Move

1

to the right side

d^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

d = - 1, d = \frac{1}{2} - \frac{3}{2} i, d = \frac{1}{2} + \frac{3}{2} i

x, x^{3} - y^{3} = 0

(x - 4)^{3} = 0

(x - 4)^{3} = 1

2 = (1 + r)^{10}

\frac{x ^{3}}{3} = 27, x

What are the solutions to the equation d^3+1=0 ?
The solutions to the equation d^3+1=0 are d=-1,d= 1/2-(sqrt(3))/2 i,d= 1/2+(sqrt(3))/2 i
Find the zeros of d^3+1=0
The zeros of d^3+1=0 are d=-1,d= 1/2-(sqrt(3))/2 i,d= 1/2+(sqrt(3))/2 i