What are the solutions to the equation 2=(1+r)^{10} ?

The solutions to the equation 2=(1+r)^{10} are r=\sqrt[10]{2}-1,r=-\sqrt[10]{2}-1

Find the zeros of 2=(1+r)^{10}

The zeros of 2=(1+r)^{10} are r=\sqrt[10]{2}-1,r=-\sqrt[10]{2}-1

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2 = (1 + r)^{10}

Decimal Notation

r = 0.07177 \dots, r = - 2.07177 \dots

Solution steps

2 = (1 + r)^{10}

Switch sides

(1 + r)^{10} = 2

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

\frac{x ^{3}}{3} = 27, x

3 x^{3} - x^{2} - 27 x + 9 = 0

1 + 1 \frac{x ^{2}}{3 ^{2}} x^{5} = n

c^{4} = 9

22 x x^{2} x + 9 = (43) 6

What are the solutions to the equation 2=(1+r)^{10} ?
The solutions to the equation 2=(1+r)^{10} are r=\sqrt[10]{2}-1,r=-\sqrt[10]{2}-1
Find the zeros of 2=(1+r)^{10}
The zeros of 2=(1+r)^{10} are r=\sqrt[10]{2}-1,r=-\sqrt[10]{2}-1