What are the solutions to the equation 2x^3+7x-9=0 ?

The solutions to the equation 2x^3+7x-9=0 are x=1,x=-1/2+i(sqrt(17))/2 ,x=-1/2-i(sqrt(17))/2

Find the zeros of 2x^3+7x-9=0

The zeros of 2x^3+7x-9=0 are x=1,x=-1/2+i(sqrt(17))/2 ,x=-1/2-i(sqrt(17))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} + 7 x - 9 = 0

x = 1, x = - \frac{1}{2} + i \frac{17}{2}, x = - \frac{1}{2} - i \frac{17}{2}

Solution steps

2 x^{3} + 7 x - 9 = 0

Factor

2 x^{3} + 7 x - 9 : (x - 1) (2 x^{2} + 2 x + 9)

(x - 1) (2 x^{2} + 2 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x^{2} + 2 x + 9 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x^{2} + 2 x + 9 = 0 : x = - \frac{1}{2} + i \frac{17}{2}, x = - \frac{1}{2} - i \frac{17}{2}

The solutions are

x = 1, x = - \frac{1}{2} + i \frac{17}{2}, x = - \frac{1}{2} - i \frac{17}{2}

d^{4} - 1 = 2

x^{3} + 2 x - 1 = 0

x^{3} - 6 x^{2} + 8 x + 2 = 0

16 y^{4} + 15 y^{2} - 1 = 0

2 x^{3} - x^{2} - x = 0

What are the solutions to the equation 2x^3+7x-9=0 ?
The solutions to the equation 2x^3+7x-9=0 are x=1,x=-1/2+i(sqrt(17))/2 ,x=-1/2-i(sqrt(17))/2
Find the zeros of 2x^3+7x-9=0
The zeros of 2x^3+7x-9=0 are x=1,x=-1/2+i(sqrt(17))/2 ,x=-1/2-i(sqrt(17))/2