What are the solutions to the equation 16y^4+15y^2-1=0 ?

The solutions to the equation 16y^4+15y^2-1=0 are y= 1/4 ,y=-1/4 ,y=i,y=-i

Find the zeros of 16y^4+15y^2-1=0

The zeros of 16y^4+15y^2-1=0 are y= 1/4 ,y=-1/4 ,y=i,y=-i

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16 y^{4} + 15 y^{2} - 1 = 0

y = \frac{1}{4}, y = - \frac{1}{4}, y = i, y = - i

Solution steps

16 y^{4} + 15 y^{2} - 1 = 0

Rewrite the equation with

u = y^{2}

and

u^{2} = y^{4}

16 u^{2} + 15 u - 1 = 0

Solve

16 u^{2} + 15 u - 1 = 0 : u = \frac{1}{16}, u = - 1

u = \frac{1}{16}, u = - 1

Substitute back

u = y^{2},

solve for

y

Solve

y^{2} = \frac{1}{16} : y = \frac{1}{4}, y = - \frac{1}{4}

Solve

y^{2} = - 1 : y = i, y = - i

The solutions are

y = \frac{1}{4}, y = - \frac{1}{4}, y = i, y = - i

2 x^{3} - x^{2} - x = 0

f, f^{4} (x) = (\frac{1}{5}) x - x^{4} + x^{2} - 1

d^{4} - 6 d^{3} + 13 d^{2} - 12 d + 4 = 0

780 n^{2} + 26 n^{3} = 2999134

x^{3} - 3 x^{2} - 41 x = 0

What are the solutions to the equation 16y^4+15y^2-1=0 ?
The solutions to the equation 16y^4+15y^2-1=0 are y= 1/4 ,y=-1/4 ,y=i,y=-i
Find the zeros of 16y^4+15y^2-1=0
The zeros of 16y^4+15y^2-1=0 are y= 1/4 ,y=-1/4 ,y=i,y=-i