What are the solutions to the equation (x+2)^3+(x-1)^2=0 ?

The solutions to the equation (x+2)^3+(x-1)^2=0 are x\approx-5.47340…

Find the zeros of (x+2)^3+(x-1)^2=0

The zeros of (x+2)^3+(x-1)^2=0 are x\approx-5.47340…

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(x + 2)^{3} + (x - 1)^{2} = 0

x \approx - 5.47340 \dots

Solution steps

(x + 2)^{3} + (x - 1)^{2} = 0

Expand

(x + 2)^{3} + (x - 1)^{2} : x^{3} + 7 x^{2} + 10 x + 9

x^{3} + 7 x^{2} + 10 x + 9 = 0

Find one solution for

x^{3} + 7 x^{2} + 10 x + 9 = 0

using Newton-Raphson:

No Solution for

x \in R

x \approx - 5.47340 \dots

The solution is

x \approx - 5.47340 \dots

- 2 x = - 2 x^{3} - 5

x^{4} - 16 x = 0

(2 x + 1)^{3} = 125

x^{4} - 9 = 0

z^{4} - 25 = 0

What are the solutions to the equation (x+2)^3+(x-1)^2=0 ?
The solutions to the equation (x+2)^3+(x-1)^2=0 are x\approx-5.47340…
Find the zeros of (x+2)^3+(x-1)^2=0
The zeros of (x+2)^3+(x-1)^2=0 are x\approx-5.47340…