What are the solutions to the equation (x-3)(5x+1)=0 ?

The solutions to the equation (x-3)(5x+1)=0 are x=3,x=-1/5

Find the zeros of (x-3)(5x+1)=0

The zeros of (x-3)(5x+1)=0 are x=3,x=-1/5

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(x - 3) (5 x + 1) = 0

x = 3, x = - \frac{1}{5}

Solution steps

(x - 3) (5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 5 x + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{5}

64 t - 16 t^{2} = 0

0 = x^{2} - 16

lo g_{14} (88.5)

x^{2} + 0.242 x + 0.072 = 0

\frac{6 ^{4}}{4} + \frac{36 \cdot 36}{2} - \frac{12 \cdot 6 ^{3}}{3}

What are the solutions to the equation (x-3)(5x+1)=0 ?
The solutions to the equation (x-3)(5x+1)=0 are x=3,x=-1/5
Find the zeros of (x-3)(5x+1)=0
The zeros of (x-3)(5x+1)=0 are x=3,x=-1/5