What are the solutions to the equation 25=15(1+r)^5 ?

The solutions to the equation 25=15(1+r)^5 are r=\sqrt[5]{5/3}-1

Find the zeros of 25=15(1+r)^5

The zeros of 25=15(1+r)^5 are r=\sqrt[5]{5/3}-1

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25 = 15 (1 + r)^{5}

Decimal Notation

r = 0.10756 \dots

Solution steps

25 = 15 (1 + r)^{5}

Switch sides

15 (1 + r)^{5} = 25

Divide both sides by

15

(1 + r)^{5} = \frac{5}{3}

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

x^{5} - 5 x^{3} + 4 x = 0

t^{3} - 6 t^{2} + 6 = 0

x^{3} + 3 x^{2} + 3 x + 18 = 0

x^{6} + 28 x^{3} + 16 = 0

(x + 2)^{3} = 0

What are the solutions to the equation 25=15(1+r)^5 ?
The solutions to the equation 25=15(1+r)^5 are r=\sqrt[5]{5/3}-1
Find the zeros of 25=15(1+r)^5
The zeros of 25=15(1+r)^5 are r=\sqrt[5]{5/3}-1