What are the solutions to the equation (x-1)^2(x+1)(x-3)=0 ?

The solutions to the equation (x-1)^2(x+1)(x-3)=0 are x=1,x=-1,x=3

Find the zeros of (x-1)^2(x+1)(x-3)=0

The zeros of (x-1)^2(x+1)(x-3)=0 are x=1,x=-1,x=3

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(x - 1)^{2} (x + 1) (x - 3) = 0

x = 1, x = - 1, x = 3

Solution steps

(x - 1)^{2} (x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 1 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = - 1, x = 3

x^{3} + 2 x^{2} - 1 = 0

(x^{2} - 1) \cdot (5 - x) = 0

(x^{2} + 2 x)^{2} - 5 (x^{2} + 2 x) + 6 = 0

a, a^{4} b + 2 c^{5} = d^{1} e

8 m^{3} - 104 m^{2} + 336 m = 0

What are the solutions to the equation (x-1)^2(x+1)(x-3)=0 ?
The solutions to the equation (x-1)^2(x+1)(x-3)=0 are x=1,x=-1,x=3
Find the zeros of (x-1)^2(x+1)(x-3)=0
The zeros of (x-1)^2(x+1)(x-3)=0 are x=1,x=-1,x=3