What are the solutions to the equation 133^5+110^5+84^5+27^5=n^5 ?

The solutions to the equation 133^5+110^5+84^5+27^5=n^5 are n=\sqrt[5]{133^5+110^5+84^5+14348907}

Find the zeros of 133^5+110^5+84^5+27^5=n^5

The zeros of 133^5+110^5+84^5+27^5=n^5 are n=\sqrt[5]{133^5+110^5+84^5+14348907}

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13 3^{5} + 11 0^{5} + 8 4^{5} + 2 7^{5} = n^{5}

Decimal Notation

n = 144

Solution steps

13 3^{5} + 11 0^{5} + 8 4^{5} + 2 7^{5} = n^{5}

Switch sides

n^{5} = 13 3^{5} + 11 0^{5} + 8 4^{5} + 2 7^{5}

2 7^{5} = 14348907

n^{5} = 13 3^{5} + 11 0^{5} + 8 4^{5} + 14348907

For

x^{n} = f (a)

, n is odd, the solution is

r^{3} = 8

z^{3} = - 27

(2 x^{3} + 7)^{2} + (2 x^{2} + 3)^{3} = 6 x^{2} + 6 x

n^{3} + 3 n^{2} + 2 n = 8436

x, y^{2} = x^{2} - x^{4}

What are the solutions to the equation 133^5+110^5+84^5+27^5=n^5 ?
The solutions to the equation 133^5+110^5+84^5+27^5=n^5 are n=\sqrt[5]{133^5+110^5+84^5+14348907}
Find the zeros of 133^5+110^5+84^5+27^5=n^5
The zeros of 133^5+110^5+84^5+27^5=n^5 are n=\sqrt[5]{133^5+110^5+84^5+14348907}