What are the solutions to the equation 2x^3=4^2x ?

The solutions to the equation 2x^3=4^2x are x=0,x=-2sqrt(2),x=2sqrt(2)

Find the zeros of 2x^3=4^2x

The zeros of 2x^3=4^2x are x=0,x=-2sqrt(2),x=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} = 4^{2} x

x = 0, x = - 22, x = 22

Decimal Notation

x = 0, x = - 2.82842 \dots, x = 2.82842 \dots

Solution steps

2 x^{3} = 4^{2} x

Move

4^{2} x

to the left side

2 x^{3} - 4^{2} x = 0

Factor

2 x^{3} - 4^{2} x : 2 x (x + 22) (x - 22)

2 x (x + 22) (x - 22) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 22 = 0 or x - 22 = 0

Solve

x + 22 = 0 : x = - 22

Solve

x - 22 = 0 : x = 22

The solutions are

x = 0, x = - 22, x = 22

(x^{2} + 1)^{2} = x

(x^{2} + x) (x + 6 - x^{3}) = 5 x

x^{4} + x^{2} - 8 = 0

x^{3} - x = 4

- 3 x^{2} + x^{3} = 4 x

What are the solutions to the equation 2x^3=4^2x ?
The solutions to the equation 2x^3=4^2x are x=0,x=-2sqrt(2),x=2sqrt(2)
Find the zeros of 2x^3=4^2x
The zeros of 2x^3=4^2x are x=0,x=-2sqrt(2),x=2sqrt(2)