What are the solutions to the equation 3+9x^5-20=40 ?

The solutions to the equation 3+9x^5-20=40 are x=\sqrt[5]{19/3}

Find the zeros of 3+9x^5-20=40

The zeros of 3+9x^5-20=40 are x=\sqrt[5]{19/3}

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3 + 9 x^{5} - 20 = 40

Decimal Notation

x = 1.44652 \dots

Solution steps

3 + 9 x^{5} - 20 = 40

Move

3

to the right side

9 x^{5} - 20 = 37

Move

20

to the right side

9 x^{5} = 57

Divide both sides by

9

x^{5} = \frac{19}{3}

For

x^{n} = f (a)

, n is odd, the solution is

2 y^{3} - 5 y^{2} = 1

3 x^{3} + 5 x^{2} - 16 x + 4 = 0

x^{3} + 4 x^{2} - 3 x - 2 = 0

x^{2} x - 12 = 0

x^{4} - 32 x + 10 = 0

What are the solutions to the equation 3+9x^5-20=40 ?
The solutions to the equation 3+9x^5-20=40 are x=\sqrt[5]{19/3}
Find the zeros of 3+9x^5-20=40
The zeros of 3+9x^5-20=40 are x=\sqrt[5]{19/3}