What are the solutions to the equation 2y^3-5y^2=1 ?

The solutions to the equation 2y^3-5y^2=1 are y\approx 2.57538…

Find the zeros of 2y^3-5y^2=1

The zeros of 2y^3-5y^2=1 are y\approx 2.57538…

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2 y^{3} - 5 y^{2} = 1

y \approx 2.57538 \dots

Solution steps

2 y^{3} - 5 y^{2} = 1

Move

1

to the left side

2 y^{3} - 5 y^{2} - 1 = 0

Find one solution for

2 y^{3} - 5 y^{2} - 1 = 0

using Newton-Raphson:

y \approx 2.57538 \dots

Apply long division:

\frac{2 y ^{3} - 5 y ^{2} - 1}{y - 2.57538 \dots} = 2 y^{2} + 0.15077 \dots y + 0.38829 \dots

2 y^{2} + 0.15077 \dots y + 0.38829 \dots \approx 0

Find one solution for

2 y^{2} + 0.15077 \dots y + 0.38829 \dots = 0

using Newton-Raphson:

No Solution for

y \in R

The solution is

y \approx 2.57538 \dots

3 x^{3} + 5 x^{2} - 16 x + 4 = 0

x^{3} + 4 x^{2} - 3 x - 2 = 0

x^{2} x - 12 = 0

x^{4} - 32 x + 10 = 0

3 x^{3} + 7 x^{2} + 17 x + 5 = 0

What are the solutions to the equation 2y^3-5y^2=1 ?
The solutions to the equation 2y^3-5y^2=1 are y\approx 2.57538…
Find the zeros of 2y^3-5y^2=1
The zeros of 2y^3-5y^2=1 are y\approx 2.57538…