What are the solutions to the equation 3sqrt(2)*x^2-5x-sqrt(2)=0 ?

The solutions to the equation 3sqrt(2)*x^2-5x-sqrt(2)=0 are x=sqrt(2),x=-1/(3sqrt(2))

Find the zeros of 3sqrt(2)*x^2-5x-sqrt(2)=0

The zeros of 3sqrt(2)*x^2-5x-sqrt(2)=0 are x=sqrt(2),x=-1/(3sqrt(2))

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32 \cdot x^{2} - 5 x - 2 = 0

x = 2, x = - \frac{1}{3 2}

Decimal Notation

x = 1.41421 \dots, x = - 0.23570 \dots

Solution steps

32 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 2 ( - 2 )}{2 \cdot 3 2}

(- 5)^{2} - 4 \cdot 32 (- 2) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 3 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 3 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 3 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 3 2} : 2

x = \frac{- ( - 5 ) - 7}{2 \cdot 3 2} : - \frac{1}{3 2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{3 2}

63 \cdot x^{2} + 7 x = 3

n, p = (n^{2}) + 1

(\frac{x + 1}{3}) (\frac{x - 1}{3}) = \frac{1}{3}

x, z = 5 x_{3} x^{2} y^{+} 7 y^{5}

x^{3} - 4 x^{2} - x + 1 = (x - 2)^{3}

What are the solutions to the equation 3sqrt(2)*x^2-5x-sqrt(2)=0 ?
The solutions to the equation 3sqrt(2)*x^2-5x-sqrt(2)=0 are x=sqrt(2),x=-1/(3sqrt(2))
Find the zeros of 3sqrt(2)*x^2-5x-sqrt(2)=0
The zeros of 3sqrt(2)*x^2-5x-sqrt(2)=0 are x=sqrt(2),x=-1/(3sqrt(2))