What are the solutions to the equation 3m^2+2=4,m^2+23m^2-4m^2=2-2 ?

The solutions to the equation 3m^2+2=4,m^2+23m^2-4m^2=2-2 are m=sqrt(2/3),m=-sqrt(2/3)

Find the zeros of 3m^2+2=4,m^2+23m^2-4m^2=2-2

The zeros of 3m^2+2=4,m^2+23m^2-4m^2=2-2 are m=sqrt(2/3),m=-sqrt(2/3)

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3 m^{2} + 2 = 4, m^{2} + 23 m^{2} - 4 m^{2} = 2 - 2

m = \frac{2}{3}, m = - \frac{2}{3}

Decimal Notation

m = 0.81649 \dots, m = - 0.81649 \dots

Solution steps

3 m^{2} + 2 = 4, m^{2} + 23 m^{2} - 4 m^{2} = 2 - 2

Move

2

to the right side

3 m^{2} = 2

Divide both sides by

3

m^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{2}{3}, m = - \frac{2}{3}

2 x^{2} - 5 x + 2 = 0, x - 2 \geq 0

a = 4 z^{2} + 23 z - 35

0.8 x - 1 = 1.5 x^{2}

x, x^{2} - 2 x y - 2 y^{2} = - x^{2} - 2 x y - y^{2}

x^{2} - 12 x = 28

What are the solutions to the equation 3m^2+2=4,m^2+23m^2-4m^2=2-2 ?
The solutions to the equation 3m^2+2=4,m^2+23m^2-4m^2=2-2 are m=sqrt(2/3),m=-sqrt(2/3)
Find the zeros of 3m^2+2=4,m^2+23m^2-4m^2=2-2
The zeros of 3m^2+2=4,m^2+23m^2-4m^2=2-2 are m=sqrt(2/3),m=-sqrt(2/3)