What are the solutions to the equation (x^2+x+1)/((sqrt(2)))=0 ?

The solutions to the equation (x^2+x+1)/((sqrt(2)))=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Find the zeros of (x^2+x+1)/((sqrt(2)))=0

The zeros of (x^2+x+1)/((sqrt(2)))=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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\frac{x ^{2} + x + 1}{( 2 )} = 0

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

\frac{x ^{2} + x + 1}{( 2 )} = 0

Simplify

(2) : 2

\frac{x ^{2} + x + 1}{2} = 0

Multiply both sides by

2

x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

x_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

x = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

x = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x, (x^{2} + y^{2} - 1) 3 = x^{2} y^{3}

(\frac{2 z + 1}{2}) \cdot z = z

- z^{2} + 15 - 4 z = 0

3 \cdot (x + 2)^{2} = 48

a, m (a) = 8 a^{2} + 15 a - 10

What are the solutions to the equation (x^2+x+1)/((sqrt(2)))=0 ?
The solutions to the equation (x^2+x+1)/((sqrt(2)))=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Find the zeros of (x^2+x+1)/((sqrt(2)))=0
The zeros of (x^2+x+1)/((sqrt(2)))=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2