What are the solutions to the equation 5r^2-26r=24 ?

The solutions to the equation 5r^2-26r=24 are r=6,r=-4/5

Find the zeros of 5r^2-26r=24

The zeros of 5r^2-26r=24 are r=6,r=-4/5

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5 r^{2} - 26 r = 24

r = 6, r = - \frac{4}{5}

Decimal Notation

r = 6, r = - 0.8

Solution steps

5 r^{2} - 26 r = 24

Move

24

to the left side

5 r^{2} - 26 r - 24 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 (- 24) = 34

r_{1, 2} = \frac{- ( - 26 ) \pm 34}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 26 ) + 34}{2 \cdot 5}, r_{2} = \frac{- ( - 26 ) - 34}{2 \cdot 5}

r = \frac{- ( - 26 ) + 34}{2 \cdot 5} : 6

r = \frac{- ( - 26 ) - 34}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

r = 6, r = - \frac{4}{5}

y^{2} - 6 y - 12 = 0

7 (2 n - 9) + 28 = 21

\frac{( \frac{1}{4} )}{4}

3 n^{2} + 8 n + 4

\frac{20}{7} - 12

What are the solutions to the equation 5r^2-26r=24 ?
The solutions to the equation 5r^2-26r=24 are r=6,r=-4/5
Find the zeros of 5r^2-26r=24
The zeros of 5r^2-26r=24 are r=6,r=-4/5