What are the solutions to the equation (2x^2)/3 =32 ?

The solutions to the equation (2x^2)/3 =32 are x=4sqrt(3),x=-4sqrt(3)

Find the zeros of (2x^2)/3 =32

The zeros of (2x^2)/3 =32 are x=4sqrt(3),x=-4sqrt(3)

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\frac{2 x ^{2}}{3} = 32

x = 43, x = - 43

Decimal Notation

x = 6.92820 \dots, x = - 6.92820 \dots

Solution steps

\frac{2 x ^{2}}{3} = 32

Multiply both sides by

3

2 x^{2} = 96

Divide both sides by

2

x^{2} = 48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 48, x = - 48

48 = 43

- 48 = - 43

x = 43, x = - 43

3 x^{2} + 25 x - 5 = 0

2 - 5 k = \frac{k ^{2}}{3}

t, a^{2} b^{2} t^{2} - a^{2} t = 1 - b^{2} t

43 \cdot x^{2} + 5 x - 23 = 0

d^{2} = 4 x^{2} - 12 x + 9

What are the solutions to the equation (2x^2)/3 =32 ?
The solutions to the equation (2x^2)/3 =32 are x=4sqrt(3),x=-4sqrt(3)
Find the zeros of (2x^2)/3 =32
The zeros of (2x^2)/3 =32 are x=4sqrt(3),x=-4sqrt(3)