What are the solutions to the equation 3=xx+xx+xx ?

The solutions to the equation 3=xx+xx+xx are x=1,x=-1

Find the zeros of 3=xx+xx+xx

The zeros of 3=xx+xx+xx are x=1,x=-1

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3 = xx + xx + xx

x = 1, x = - 1

Solution steps

3 = xx + xx + xx

Expand

xx + xx + xx : 3 x^{2}

3 = 3 x^{2}

Switch sides

3 x^{2} = 3

Move

3

to the left side

3 x^{2} - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

0^{2} - 4 \cdot 3 (- 3) = 6

x_{1, 2} = \frac{- 0 \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 0 + 6}{2 \cdot 3}, x_{2} = \frac{- 0 - 6}{2 \cdot 3}

x = \frac{- 0 + 6}{2 \cdot 3} : 1

x = \frac{- 0 - 6}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = 1, x = - 1

x, 3 x + 4 y (3 x^{2} + 4 y^{2}) = 0

4 x^{2} - 2 (a^{4} - b^{4}) x + a^{2} b^{2} = 0

\frac{( 6 x ^{2} )}{5} = 4.8

\frac{( n ( n + 6 ) )}{12} = 18000

\frac{2 x ^{2}}{16} = 2^{3} x

What are the solutions to the equation 3=xx+xx+xx ?
The solutions to the equation 3=xx+xx+xx are x=1,x=-1
Find the zeros of 3=xx+xx+xx
The zeros of 3=xx+xx+xx are x=1,x=-1