What are the solutions to the equation x^2=(17\mod*29) ?

The solutions to the equation x^2=(17\mod*29) are x=sqrt(493) sqrt(\mod),x=-sqrt(493) sqrt(\mod)

Find the zeros of x^2=(17\mod*29)

The zeros of x^2=(17\mod*29) are x=sqrt(493) sqrt(\mod),x=-sqrt(493) sqrt(\mod)

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x^{2} = (17 mod \cdot 29)

Solution steps

x^{2} = (17 mod 29)

Multiply the numbers:

17 \cdot 29 = 493

x^{2} = 493

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 493 mod, x = - 493 mod

Simplify

493 mod : 493 mod

Simplify

- 493 mod : - 493 mod

x = 493 mod, x = - 493 mod

- x^{2} + 2 x + 3 = x^{2} - 2 x + 3

x^{2} + 3 x = 26

\frac{25}{100} \cdot x + \frac{40}{100} (x \cdot x) = 178

- 7 x^{2} + 6 x - 1 = 0

4 x^{2} + 4 x + 1 = 36

What are the solutions to the equation x^2=(17\mod*29) ?
The solutions to the equation x^2=(17\mod*29) are x=sqrt(493) sqrt(\mod),x=-sqrt(493) sqrt(\mod)
Find the zeros of x^2=(17\mod*29)
The zeros of x^2=(17\mod*29) are x=sqrt(493) sqrt(\mod),x=-sqrt(493) sqrt(\mod)