What are the solutions to the equation x^2-20x+a^2=0 ?

The solutions to the equation x^2-20x+a^2=0 are x=10+sqrt(-a^2+100),x=10-sqrt(-a^2+100)

Find the zeros of x^2-20x+a^2=0

The zeros of x^2-20x+a^2=0 are x=10+sqrt(-a^2+100),x=10-sqrt(-a^2+100)

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x^{2} - 20 x + a^{2} = 0

x = 10 + - a^{2} + 100, x = 10 - - a^{2} + 100

Solution steps

x^{2} - 20 x + a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot a ^{2}}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot a^{2} : 2 100 - a^{2}

x_{1, 2} = \frac{- ( - 20 ) \pm 2 100 - a ^{2}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 100 - a ^{2}}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 100 - a ^{2}}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 100 - a ^{2}}{2 \cdot 1} : 10 + - a^{2} + 100

x = \frac{- ( - 20 ) - 2 100 - a ^{2}}{2 \cdot 1} : 10 - - a^{2} + 100

The solutions to the quadratic equation are:

x = 10 + - a^{2} + 100, x = 10 - - a^{2} + 100

2 x^{2} + 4 - 3 x = 0

x, x^{2} - y^{2} + x + y = 0

- 34 x^{2} + 135 x - 449 = 0

\frac{3 x ^{2}}{5} = 6

(x + 2)^{3} = x^{3} - 4

What are the solutions to the equation x^2-20x+a^2=0 ?
The solutions to the equation x^2-20x+a^2=0 are x=10+sqrt(-a^2+100),x=10-sqrt(-a^2+100)
Find the zeros of x^2-20x+a^2=0
The zeros of x^2-20x+a^2=0 are x=10+sqrt(-a^2+100),x=10-sqrt(-a^2+100)